Subnetting (TJKN)

 

Nama : Muhammad Ali Haydar

Kelas : XI TJKT 1

Mapel : TJKN

No Absen : 23

 

Selesaikan soal subnetting berikut:

192.168.1.35/27 = IP Net: 192.168.1.32  , IP BC: 192.168.1.63   ,  IP Awal: 192.168.1.33    , IP Akhir: 192.168.1.62

192.168.1.135/25 = IP Net: 192.168.1.128  , IP BC: 192.168.1.255   ,  IP Awal: 192.168.1.129    , IP Akhir: 192.168.1.254

192.168.1.129/27 = IP Net: 192.168.1.128 , IP BC: 192.168.1.159  ,  IP Awal: 192.168.1.129   , IP Akhir: 192.168.1.158

192.168.1.240/27 = IP Net: 192.168.1.224  , IP BC: 192.168.1.255   ,  IP Awal: 192.168.1.255   , IP Akhir: 192.168.1.254

192.168.1.190/26 = IP Net: 192.168.1.128  , IP BC: 192.168.1.191   ,  IP Awal: 192.168.1.129    , IP Akhir: 192.168.1.190

192.168.1.1/25 = IP Net: 192.168.1.0  , IP BC: 192.168.1.127   ,  IP Awal: 192.168.1.1    , IP Akhir: 192.168.1.126

192.168.1.64/26 = IP Net: 192.168.1.64  , IP BC: 192.168.1.127   ,  IP Awal: 192.168.1.65   , IP Akhir: 192.168.1.126

192.168.1.35/28 = IP Net: 192.168.1.32  , IP BC: 192.168.1.47   ,  IP Awal: 192.168.1.33    , IP Akhir: 192.168.1.46

192.168.1.15/28 = IP Net: 192.168.1.0  , IP BC: 192.168.1.15   ,  IP Awal: 192.168.1.1    , IP Akhir: 192.168.1.14

192.168.1.9/29 = IP Net:  192.168.1.8  , IP BC: 192.168.1.15   ,  IP Awal: 192.168.1.9    , IP Akhir: 192.168.1.14